查看字典内部方法，使用help(list)、dir(list)来查看。

1、clear：清除字典所有内容

D.clear() -> None. Remove all items from D.

dic1 = {
    'k1':'v1','k2':'v2'}dic1.clear()print(dic1)#屏幕打印{},dic1已被清空

2、copy：复制字典内容(浅拷贝)

D.copy() -> a shallow copy of D

dic1 = {
    'k1':'v1','k2':'v2','k3':'v3'}dic2 = dic1.copy()print(dic2)#屏幕打印{'k1':'v1','k2':'v2','k3':'v3'}

3、fromkeys：从列表或其他对象来创建字典，S为新字典的keys，v为新字典中的值（可以不赋值）

dict.fromkeys(S[,v]) -> New dict with keys from S and values equal to v.

v defaults to None.

li1 = ['name','age','sex']dic1 = dict.fromkeys(li1)print('New Dic:%s' % (dic1))dic1 = dict.fromkeys(li1,'10')print('New Dic:%s' % (dic1))#屏幕打印：New Dic:{'name': None, 'age': None, 'sex': None}                New Dic:{
    'name': '10', 'age': '10', 'sex': '10'}

4、get：从字典中get指定的key的值，如果key不存在，则返回设置的默认值，不设置默认值则为None

D.get(k[,d]) -> D[k] if k in D, else d.  d defaults to None.

dic1 = {
    'k1':'v1','k2':'v2'}result = dic1.get('k1','None')print(result)result = dic1.get('k3','None')print(result)#屏幕打印：v1                None

5、has_key：检查字典中是否存在这个key，如果没有则返回False，有则返回True

D.has_key(k) -> True if D has a key k, else False

dic1 = {
    'k1':'v1','k2':'v2'}result = 'k1' in dic1print(result)#python3中已经无此用法，所以用in取代这种方法

6、items：将字典中的键值对返回为列表内部为元组，[(键，值)，(键，值)]的形式，循环时可以使用 for k,v in dic.items()

D.items() -> list of D's (key, value) pairs, as 2-tuples

dic1 = {
    'k1':'v1','k2':'v2'}result = dic1.items()print(result)#屏幕打印：dict_items([('k1', 'v1'), ('k2', 'v2')])

7、iteritems:将字典中所有的键值对返回为一个迭代器

D.iteritems() -> an iterator over the (key, value) items of D

8、iterkeys：将字典中的所有键返回一个迭代器

D.iterkeys() -> an iterator over the keys of D

9、itervalues：将字典中的所有值返回一个迭代器

D.itervalues() -> an iterator over the values of D

#python3.6中已经删除了以上几种用法，故不写代码

10、keys：返回字典中所有的key为一个列表

D.keys() -> list of D's keys

dic1 = {
    'k1':'v1','k2':'v2'}result = dic1.keys()print(result)#屏幕打印：dict_keys(['k1', 'k2'])

11、pop：返回字典中指定的键值并移除指定的键的键值对项，如果没有找到指定的键将返回定义的内容，如果没有定义则报错keyError

D.pop(k[,d]) -> v, remove specified key and return the corresponding value.

If key is not found, d is returned if given, otherwise KeyError is raised

dic1 = {
    'k1':'v1','k2':'v2'}result = dic1.pop('k1','Error')print(result)result = dic1.pop('k3','Error')print(result)#屏幕打印：v1                Error

12、popitem：返回并删除字典中的最后位置的键值对，如果字典已经为空则报错KeyError

D.popitem() -> (k, v), remove and return some (key, value) pair as a

2-tuple; but raise KeyError if D is empty.

dic1 = {
    'k1':'v1','k2':'v2','k3':'v3'}result = dic1.popitem()print(result)#屏幕打印：('k3', 'v3')

13、setdefault：如果字典不存在这个key，则创建，值为None，如果已经存在key，就返回这个key

D.setdefault(k[,d]) -> D.get(k,d), also set D[k]=d if k not in D

dic1 = {
    'k1':'v1','k2':'v2','k3':'v3'}result = dic1.setdefault('k3')print(result)result = dic1.setdefault('k4')print(result)print(dic1)#屏幕打印：v3                None                {
     'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': None}

14、update：把另一个字典的键值对更新到当前字典中

D.update([E, ]**F) -> None. Update D from dict/iterable E and F.

If E present and has a .keys() method, does: for k in E: D[k] = E[k]

If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v

In either case, this is followed by: for k in F: D[k] = F[k]

dic1 = {
    'k1':'v1','k2':'v2','k3':'v3'}dic2 = {
    'k1':'v5'}dic1.update(dic2)print(dic1)dic2 = {
    'k4':'v4'}dic1.update(dic2)print(dic1)#屏幕打印：{'k1': 'v5', 'k2': 'v2', 'k3': 'v3'}                {
    'k1': 'v5', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}

15、values：返回字典中所有的值为一个列表

D.values() -> list of D's values

dic1 = {
    'k1':'v1','k2':'v2','k3':'v3'}result = dic1.values()print(result)#屏幕打印：dict_values(['v1', 'v2', 'v3'])

以上为本人课堂笔记，如有不全，欢迎补充！